Hallo
I am facing a weird behavior with these boards, the pin 7 of the first shift register doesn't switch, but the pin 7 pf the second switch register switches bot itself and the pin 7 of the first register, here is my code:
//Pin connected to ST_CP of 74HC595
int latchPin = 7;
//Pin connected to SH_CP of 74HC595
int clockPin = 13;
////Pin connected to DS of 74HC595
int dataPin = 11;
void setup() {
//set pins to output because they are addressed in the main loop
pinMode(latchPin, OUTPUT);
Serial.begin(9600);
}
void loop() {
if (Serial.available() > 3) {
//preparamos para enviar datos
digitalWrite(latchPin, 0);
digitalWrite(8, HIGH); // Deactivates master reset ESTO VA FUERA DEL LOOP O NO?
//contamos los numeros de shift registers conectados
for (int i=0 ; i < 4; i++)
{
//byte a=(byte) Serial.read() - '0';
//leimos el contenido del puerto serial
byte a=(byte) Serial.read();
//move 'em out
shiftOut(dataPin, clockPin, a);
//digitalWrite(latchPin, 1);
Serial.println(a);
}
digitalWrite(latchPin, 1);
}
}
// the heart of the program
void shiftOut(int myDataPin, int myClockPin, byte myDataOut) {
// This shifts 8 bits out MSB first,
//on the rising edge of the clock,
//clock idles low
//internal function setup
int i=0;
int pinState;
pinMode(myClockPin, OUTPUT);
pinMode(myDataPin, OUTPUT);
//clear everything out just in case to
//prepare shift register for bit shifting
digitalWrite(myDataPin, 0);
digitalWrite(myClockPin, 0);
//for each bit in the byte myDataOut�
//NOTICE THAT WE ARE COUNTING DOWN in our for loop
//This means that %00000001 or "1" will go through such
//that it will be pin Q0 that lights.
for (i=7; i>=0; i--) {
digitalWrite(myClockPin, 0);
//if the value passed to myDataOut and a bitmask result
// true then... so if we are at i=6 and our value is
// %11010100 it would the code compares it to %01000000
// and proceeds to set pinState to 1.
if ( myDataOut & (1<<i) ) {
pinState= 1;
}
else {
pinState= 0;
}
//Sets the pin to HIGH or LOW depending on pinState
digitalWrite(myDataPin, pinState);
//register shifts bits on upstroke of clock pin
digitalWrite(myClockPin, 1);
//zero the data pin after shift to prevent bleed through
digitalWrite(myDataPin, 0);
}
//stop shifting
digitalWrite(myClockPin, 0);
}